By B. Hague D.SC., PH.D., F.C.G.I. (auth.)

ISBN-10: 0412207303

ISBN-13: 9780412207303

ISBN-10: 9400958412

ISBN-13: 9789400958418

The critical adjustments that i've got made in getting ready this revised variation of the publication are the subsequent. (i) Carefuily chosen labored and unworked examples were additional to 6 of the chapters. those examples were taken from classification and measure exam papers set during this college and i'm thankful to the collage court docket for permission to exploit them. (ii) a few extra subject at the geometrieaI program of veetors has been included in bankruptcy 1. (iii) Chapters four and five were mixed into one bankruptcy, a few fabric has been rearranged and a few additional fabric additional. (iv) The bankruptcy on int~gral theorems, now bankruptcy five, has been accelerated to incorporate an altemative evidence of Gauss's theorem, a treatmeot of Green's theorem and a extra prolonged discussioo of the category of vector fields. (v) the single significant switch made in what at the moment are Chapters 6 and seven is the deletioo of the dialogue of the DOW out of date pot funetioo. (vi) A small a part of bankruptcy eight on Maxwell's equations has been rewritten to provide a fuller account of using scalar and veetor potentials in eleetromagnetic conception, and the devices hired were replaced to the m.k.s. system.

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**Example text**

C]d = la. b, d] e - la, b, e] d. a] b [e, d, b] a + [e, d, a] b. X By these we now have that d = [e, d, b] a - [e, d, a] b ra, b, e] + ra, b, d] e , the denominator being non-zero since a, b, e are non-planar. Hence d = [b, e, d] a + [e, a, d] b + ra, b, d] e. ra, b, e] 7. LiBe and Surface IntegraJs as scalar Products. In fig. 18, let e be any eurve drawn in a veetor field and ds an element of are along it Ffgure 18 Tangentialline integrai of a vector at any point P. Let V denote the veetor at P in a direction making an angle 8 with that of the length element.

E. A. (B x C) is the volume of the parallelepiped which ha!! A. B. l. 19) so that the dot and cross may be interehanged at will. Three veetors, therefore, have six identical scalar triple products which may be written concisely as i j k A", All A. B", BII B. k). B", By B. C", CII C. C", C y C. 19 bis) When three veetors lie in a plane, the volume of the parallelepiped is zero, and conversely; hence a necessary and sufficient condition for three veetors to be co-planar is that their sealar triple product vanishes.

Similarly, the plane {J contains OB and is perpendicular to the plane OCA, and the pIane 'Y contains OC and is perpendicular to the plane OAB. Show that the pIanes a, {J, 'Y intersect in a line. 17. The veetors i, j, k are non-planar. Find the veetor equation of the line joining the points A and B with positian vectors i - 2j + k and i - j + 3k, respectiveIy, and show that the point P with position veetor i - Sj - Sk lies on AB. Find also the vector equation of the plane which passes through AB and the point C with position veetor k.

### An Introduction to Vector Analysis For Physicists and Engineers by B. Hague D.SC., PH.D., F.C.G.I. (auth.)

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